Question

Find the value of the discriminant. Then describe the number and type of roots for the equation.
x^2-v+9=0 Could Someone help me with this problem

Answer 1

is v a constant???

Answer 2

the value of discriminant depends on value of v....
do you know what is v?

Answer 3

no

Answer 4

i think the solution of x in x^2-v+9=0 is
\[x=\pm \sqrt{v-9} \]
we don't need to find the discriminant ...
it all depends on the value of v if the root is real or non-real...

Answer 5

since in the equation the coefficent of x is 0
hence \[discriminent=\sqrt{b ^{2}-4ac}\]
put b=0
then,\[discriminant=\sqrt{0^{2}-4(-v+9)}=2\sqrt{v-9}\]

Answer 6

solution for x is given by
\[x=[-b \pm \sqrt{b ^{2}-4ac}]/2a\]
\[x=[-0\pm \sqrt{0^{2}+4(v-9)}]/2(1)\]
\\[x=\pm2\sqrt{v-9}/2(1)\]\[x=\pm \sqrt{v-9}\]