Question

Please help! (attachment)

Answer 1

"assume a steady rate of decliine"

notice that as "year" increases, "total" is going down, or decreasing \(\bf \begin{array}{cccllll}
\textit{something }&\textit{varies inversely to }&\textit{something else}\\ \quad \\
\textit{something }&=\cfrac{{\color{red}{ \textit{some value }}}}{\textit{something else}}\\ \quad \\
y&=\cfrac{{\color{red}{ n}}}{x}
&&\implies y=\cfrac{{\color{red}{ n}}}{x}
\end{array}
\\ \quad \\
year=1990\qquad total=149,666\quad thus
\\ \quad \\
year=\cfrac{{\color{red}{ n}}}{total}\implies 149,666=\cfrac{{\color{red}{ n}}}{1990}\)

so find "n", or "constant of variation"
once you find the constant of variation, plug it back in the equation, to get the linear equation for it

Answer 2

.... actaully should have been anyhow, got the labels a bit mixed up \(\bf year=1990\qquad total=149,666\quad thus
\\ \quad \\
total=\cfrac{{\color{red}{ n}}}{year}\implies 149,666=\cfrac{{\color{red}{ n}}}{1990}\\\)

Answer 3

to predict the pilots in 2003,
use that equation and just make total=x=2003

Answer 4

so 149,666 = n/1990 would be the equation?

Answer 5

@jdoe0001

Answer 6

@ankit042

Answer 7

@jdoe0001 I don't understand why you put 1990 when its asking to use 1995 and 1980 to find a linear equation. Can you explain that to me please?

Answer 8

@ankit I got this as a linear equation. am I correct or no? y = -2194.9x + 4512805.5.

I found the slope and then plugged it in the y=mx+ b formula.

Answer 9

Yes! it is correct. As it is already mentioned to use 1995 and 1985 as benchmark so using y2-y1/x2-x1 you can find the slope and then plug in to find constant

Answer 10

Thank you!

Answer 11

sorry was a bit caught up....anyhow... yes... you're correct... it had to do with geting the slope

Answer 12

It's fine! thank you so much for trying to help (: