The company also discovered that it costs $15.50 to produce 3 widgets, $23.50 to produce 7 widgets, and $56 to produce 12 widgets. What is the total cost producing 5 widgets?
It's a quadratic function, and you have three given points. The form of a quadratic function is ax2+bx+c=0 You have three given (x, y) points: (3, 15.50) (7, 23.5) (12, 56) Insert each of the three points in the equation. You will get three equations in three unknowns, a, b, and c. Solve the system of equations for a, b, and c. Then insert a, b, and c in the quadratic equation above. Finally, evaluate it for x = 5.
yeah i know those points. but i dont know which variable to plug them into.
@wrstlr3232
@SolomonZelman
\[9a+3b+c = 15.5\] \[49a+7b+c=23.5\] \[144a+12b+c=56\] solve the system
a= 1/2 b= -3 c= 20 ????
a and b are right. I got 19.5 for c
how ?
its 20.. i just calculated it
Now substitute 5 into the quadratic equation: 1/2(25)+-3(5)+20 = ? The cost to produce 5 widgits
i dont get that part..
\[ax ^{2}+bx+c=0\]
1/2(5^2)+-3(5)+20=0 12.5-15+20 = 17.50 so it costs 17.50 to produce 5 widgits (5, 17.50)
a=1/2 b=-3 c=20 substituted those values for a, b, c...used 5 for the x value since that's what we're looking for
thanks can you help me with one more problem?
sure
Looks very similar to last problem
any idea ?
4a+2b+c=45 16a+4b+c=143 100a+10b+c=869 solve the systems
Let me know what you got for a, b, & c...I've determined those
Is there any more to the question?\[c(x)=9x ^{2}-5b+19\]
a= 9 b= -5 c= 19
Yes...Great.
yeah i have to find the total cost of producing 1 calculator
substitute a 1 in for x in the c(x) equation I showed up a few
c(x)=9x2−5b+19 c(x) = 9(1)-5(1)+19 =
23?
yes
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