write an equation of the line that passes through (2,-7) and is parallel to the line x=5. Please show all steps!
x=2 line
Please show your work
there is nothing in this very easy ...which is the line parallel to x=5 and passing through the point x=2 ...the only possibility is x=2 line
hmmm
understood?
kind of, i still need to show some sort of work of how i get the answer though
ok wait a sec?
ok :)
It would help if you used equations like y=mx+b in order to show me :)
a line with equation x=5 has slope equal to \(\infty\) (becuase it is a vertical line) ok?
look at the graph once vertical axis is x axis
@helder_edwin ok...and?
well this is not exactly correct but u can think of the slope as \[\large m=\frac{k}{0} \] where k is any constant.
now the formula for the slope is \[\large m=\frac{y_1-y_2}{x_1-x_2} \] replacing m above and the point given u would get \[\large \frac{1}{0}=\frac{y-(-7)}{x-2}=\frac{y+7}{x-2} \] and from this \[\large 1(x-2)=0(y+7)\] or \[\large x-2=0 \qquad\text{or}\qquad x=2 \]
in that sense literally by applying the line equation of a line with slope m and passes through a point (x*,y*) is y-y* = m(x-x*) following this (y-(-7)) =infinity ( x-2) (y+7)/infinity = x-2 but any number/infinity = 0 therefore x-2 =0 which implies x=2 is the line.
got it @ineedhelp77 ??
I'm still thinking...
whats the problem?
It's just that the way you guys solved the problem is waaaaaaaaaay different than the way I'm learning how to and my head is just spinning.
take your time.
if i were to solve this on paper, instead of writing infinity, would I write 0?
lets solve it your way...what is the first step which you think?
well, my teachers always told me to write y=mx+b first
actually the equation of a line in most general form is not that .that is the problem
No, but then I would usually take the same slope and then plug everything in
y = mx + c is a simplified form of a line with some conditions
i'll teach you the most general method if you wish which helps you solve any equation of a line
That would be nice! I've never even seen y=mx+c before
that is the same equation you wrote we always use c instead of b
ok lets start
Oh ok
here, we always use b
see first thing is to find slope ...do you know how to do this..if yes we'll go to next step
yes i do know
to remind you if m is the slope and we have two points (x1,y1) and (x2,y2) then m=(y2-y1)/(x2-x1) ...are you ok with this?
yes
then you can write (y2-y1) = m (x2-x1) ..ok?
so is this how i start the problem? by writing this?
wait a sec let me complete...you understood the previous step?
yes
then for any general point (x,y) we can write the equation of a line by replacing (x2,y2) with (x,y)....then the equation becomes {(y-y1) = m (x-x1)} this is the equation of a line in most general form
ok. so how do i use it for this problem?
dont i need to find the slope first? how would i do that with only one point given?
now first find slope m=(y2-y1)/(x2-x1) but as you know x=5 line value of x is constant then slope becomes infinity...understood?
what should i write instead of infinity?
you write infinity symbol ∞
ok with it?
oh ok thanks
how would the distributing part work? its infinity(x-2)
in given question the line which we need is parallel to x=5 then its slope should also be infinity ok?
ok...
now as you can see we have slope m and a point (2,-7)
yes...
by using the equation (y-(-7)) = infinity (x-2)
okay i got that, but how would i distribute that
you know (any number/infinity )= 0 ??
is this understood?
yeah, but arnt i supposed to multiply?
you can take the infinity to the L.H.S and write (y+7)/infinity = (x-2)
ok with this?
LHS?
left hand side :)
oooh okayyy
then what do you get??
x=2!!! OMG THANKS SO MUCH
You're the best thanks so much! :D
if you wish i'll say something which you may follow
sorry, i have to go now. its dinner time and i have to finish the rest of my homework. thanks anyway though!
goodbye! and thanks again!
ok but what i wanted to say was..don't blindly follow the procedure..use ur common sense by drawing graphs...just by thinking you could solve the above problem
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