I will award you! :) A punter on Westview High School's football team kicks a ball straight up from 5 feet above the ground with an initial upward velocity of 45 feet per second. The height of the ball above ground after t seconds is given by the equation h = –16t^2 + 45t + 5, where h is the height of the ball in feet and t is the time in seconds since the punt. What is the maximum height of the ball, to the nearest foot? A. 37 feet B. 38 feet C. 39 feet D. 400 feet
@Hero
@SolomonZelman
So, we are having a case of a parabola. \(\normalsize\color{black}{ h = –16t^2 + 45t + 5}\)
What should i solve for?
the maximum point is labeled.
it is 36.641, which is approximately 37.
great. thanks! :)
I actually have one more question. could you help me one more time?
I wanted to work that one out by hand without graphing, but it is a very dirty equation that would involve very stupid fractions... yw
Join our real-time social learning platform and learn together with your friends!