Which logarithmic graph can be used to approximate the value of y in the equation 4^y=5

Question

anonymous · Answer

I can't post the graphs... can somebody please tell me how to graph this?

anonymous · Answer

It's logarithmic, if that helps at all.

solomonzelman · Answer

$\large\color{black}{ 4^y=5}$

$\large\color{black}{ \log 4^y=\log 5}$

$\large\color{black}{ y~\log 4=\log 5}$

$\large\color{black}{ y=\log 5 \div \log 4}$

$\large\color{black}{ y=\log_45}$

solomonzelman · Answer

https://www.desmos.com/calculator/gk8bjtlxkg

solomonzelman · Answer

Just a vertical line

anonymous · Answer

Uh oh...  All of my graphs have curves...

anonymous · Answer

A curve.  excuse me.

solomonzelman · Answer

$\large\color{black}{ \log_45=1.16}$

solomonzelman · Answer

Just a vertical line

solomonzelman · Answer

maybe you mean    $\large\color{black}{ 4^y=x}$  ?

anonymous · Answer

Unfortunately, no.  I typed it how the problem did.

solomonzelman · Answer

well, y is in the exponent, but in this case, you have x set to zero, and all you get is the approximation of y=1.16.

it is just a vertical line, as far as I know...

solomonzelman · Answer

http://www.wolframalpha.com/input/?i=4%5Ey%3D5

anonymous · Answer

Ok.  Maybe I'm just missing something...  oi

solomonzelman · Answer

the blue is the exponential that you are talking about

anonymous · Answer

OK-  Unfortunately, none of my graphs look like that.

anonymous · Answer

I've got it!  The 1.16 is an asymptote, so I just need to look for a graph that looks like it has an asymptote just above 1!

anonymous · Answer

Yay!

solomonzelman · Answer

yes, apparently it is so...

anonymous · Answer

Thank you!