Fan&Medal
Happy Birthday! Or maybe Happy Un-Birthday? Either way, here is a fun birthday trick. Take the month you were born in. Multiply it by 4, add 13, multiply by 25, subtract 200, add the day you were born, multiply by 2, subtract 40, multiply by 50, add the last two digits of your birth year, subtract 10500…. viola! Your birth date! Impress your friends! Now, use your birthday for some more math fun. You can locate graph paper here. Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day. Write your equation below. Using complete sentences, explain how to convert your birthday function into standard form. Graph your function. Include your graph below. Using complete sentences, explain how to find the average rate of change for f(x) from x = 4 to x = 7.
i just need help with number 3 @KlOwNlOvE @OOOPS @pgpilot326 @dan815 @SolomonZelman
Can you do the first part of the problem.?
i already did those all i need is to graph the function
what function did you make?
@SolomonZelman
i'd help but i've got to run right now. if this post is still here later today, i'll see if I can help. good luck!
i really need help D:
Maybe you meant that it is \(\normalsize\color{black}{ f(x)=2(x-12)^2+8\LARGE\color{white}{ \rm │ }}\) ?
yea i did thanks
so how do i graph it do i just put it in a parabola thing in the box and u plug in numbers for X ?
\(\normalsize\color{black}{ f(x)=2(x-12)^2+8\LARGE\color{white}{ \rm │ }}\) https://www.desmos.com/calculator/glttr1vz6v
(12,8) is the minimum point. That you can see by looking at the graph, or comparing it to the standard formula of the parabola.
yea but the graph they gave me goes to 10
\(\normalsize\color{black}{ f(4)=2(4-12)^2+8=2(-8)^2+8=128+8=136 \LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{black}{ f(7)=2(7-12)^2+8 =2(-5)^2+8=50+8=58 \LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{black}{ f(4)-f(7)=136-58=78 \LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{black}{ 78\div3=26~~~~~(average~~rate)~ \LARGE\color{white}{ \rm │ }}\)
Up to 10 ?
yea
so if its 12 then the graph thing has to be 10 11 12 13 14 and plug into x
@SolomonZelman
@wio
@nikato
I'm not sure. But u can just plug in numbers for x to find y and then graph those points
all i need is the number and i will find it i think its 12
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