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Find an explicit rule for the nth term of the sequence. 3, -12, 48, -192, ...
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@johnweldon1993
\(\large\color{black}{ Common~~ratio=a_{n}\div a_{n-1}=a_2 \div a_1=(-12)\div 3=-4\LARGE\color{white}{ \rm │ }}\)
an = a1(r)^(n-1) just plug in the numbers and you get an = 3(-4)^(n-1)
You weren't right, but close, your common ratio is not 4, but `-4`.
And it is to the power of `n-1`, not to the power of `n+1`.
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got it (: @SolomonZelman
Yes, that would be correct.
Good work :)
youre the best!!
Not really, but tnx :)
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