@johnweldon1993
The position of an object at time t is given by s(t) = 1 - 12t. Find the instantaneous velocity at t = 2 by finding the derivative.
@wio
last problem i swear!!
Well what is the derivative of our function? \[\large s(t) = 1 - 12t\] \[\large s'(t) = ?\]
12? im really bad at derivatives
Close Well first, remember the derivative is just the slope of a function at any given point So firstly, if we just had s(t) = 1 this would be horizontal line, with no slope right? so that means the derivative of a constant = 0 And so we have s(t) = -12t Well the derivative of a term with a variable, is just the term But notice however, the term is -12, not 12 so the derivative of our function is -12 \[\large s(t) = 1 - 12t\] \[\large s'(t) = -12\]
oh! i was so close :/
And what that tells us, is that ANYWHERE you look on the derivative graph of 1 - 12t...the slope will be -12 so, it doesnt matter if they want the derivative at t = 2....t = 4....or t = 10000 no matter what, it is -12
thats it?! that was so easy
Math generally is, as long as you understand the approach
thanks(:
anytime!
@jays2hot
Join our real-time social learning platform and learn together with your friends!