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Mathematics 13 Online
OpenStudy (anonymous):

@johnweldon1993

OpenStudy (anonymous):

The position of an object at time t is given by s(t) = 1 - 12t. Find the instantaneous velocity at t = 2 by finding the derivative.

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

last problem i swear!!

OpenStudy (johnweldon1993):

Well what is the derivative of our function? \[\large s(t) = 1 - 12t\] \[\large s'(t) = ?\]

OpenStudy (anonymous):

12? im really bad at derivatives

OpenStudy (johnweldon1993):

Close Well first, remember the derivative is just the slope of a function at any given point So firstly, if we just had s(t) = 1 this would be horizontal line, with no slope right? so that means the derivative of a constant = 0 And so we have s(t) = -12t Well the derivative of a term with a variable, is just the term But notice however, the term is -12, not 12 so the derivative of our function is -12 \[\large s(t) = 1 - 12t\] \[\large s'(t) = -12\]

OpenStudy (anonymous):

oh! i was so close :/

OpenStudy (johnweldon1993):

And what that tells us, is that ANYWHERE you look on the derivative graph of 1 - 12t...the slope will be -12 so, it doesnt matter if they want the derivative at t = 2....t = 4....or t = 10000 no matter what, it is -12

OpenStudy (anonymous):

thats it?! that was so easy

OpenStudy (johnweldon1993):

Math generally is, as long as you understand the approach

OpenStudy (anonymous):

thanks(:

OpenStudy (johnweldon1993):

anytime!

OpenStudy (geekfromthefutur):

@jays2hot

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