Question

Can someone tell me how to determine the period of this?

Answer 1

what time of the month is it?

Answer 2

;p

Answer 3

haha so funny no seriously :P

Answer 4

i mean the k value ;P

Answer 5

the k value?

Answer 6

yes

Answer 7

like period=360/k i need to know how to find k

Answer 8

lol ok

Answer 9

this makes no sense

Answer 10

your question doesnt match to your other question lol

Answer 11

I'm doing 2 things at once. Give me a few minutes and I can figure it out.

Answer 12

lol whats up man

Answer 13

okay thank you @wrstlr3232

Answer 14

Part a) 3.1cos(Bt)+12.18
Does that seem what you are looking for? That's the trig answer.

Answer 15

yea for part a) thats the answer I have too but is there a way to find the period (k value) or the D value?

Answer 16

sure, the period is going to be 1 or 2pi/2pi . The graph isn't changing, so it will stay the same.

Answer 17

okay so its just 1

Answer 18

yep, the period is. But you don't need to put the period into the equation. It's just given that it is 2pi. (like 1y is the same as y)

Answer 19

You actually want to put it as 3.1cos(2pi t)+12.18
I'm trying to figure out the second part

Answer 20

okay

Answer 21

Nov 23 and Jan 16th.
Bleck, that was a rough one. I haven't done a problem like that for a while. Did you figure out what days it it would be for part B?

Answer 22

No, I cant figure it out haha when I graph it it shows at 13.5 hours is on 12.9 but im not sure what that means (13.5,12.9) is the coordinates

Answer 23

Yeah, I see what you're saying. So the graph would look like this The hours of sunlight happens twice a year. The graph can also be described in a circle(not drawn to scale at all haha) You'd have to find where on the circle or the graph 13.5 is. your coordinates will be (x,13.5) and you'll have 2 of them