Question

help me please

Answer 1

Are you doing this by hand or with software?

Answer 2

It's gonna be easier though with software :)

Answer 3

software

Answer 4

Is there one you use in particular?

Answer 5

[This is very easy to do in "R" if you know about it, and it's completely free]

Answer 6

Lol, I had Algebra at FLVS, who's calss are you in?

Answer 7

I'm in no one's class :) I'm actually done with school

Answer 8

I meant breezy, lol

Answer 9

oh silly me haha

Answer 10

i had this class before too, ms. prince, and was curious who she had.

Answer 11

and I don't use it

Answer 12

Oh I hate that, because I was going to email your teacher about how you're cheating and aren't allowed to use this website (seriously, you shouldn't be asking questions here) and now I can't do that since you're in another state.

Answer 13

So, Kirby, please make sure you only give conceptual help like you were doing and not doing the work for her, you seem to be one of the few that are actually helping, it's just that students are not supposed to be using this site for any reason.

Answer 14

actually im not cause I need help im not asking for answers

Answer 15

I clearly said I need help

Answer 16

I'm looking at your profile and past questions and you are abusing the system.

Answer 17

Then you should only ask how to create scatter plots , or how to find the line of best fit.

Answer 18

Copying and pasting the question is a big no no

Answer 19

Well what I could suggest is for software, you could download this: http://www.r-project.org/

and then you can just enter these commands:

time<-c(52,37,31,9,26,40,22,10,45,34,19,60)
grade<-c(95,84,72,58,77,86,72,43,90,81,62,98)
model<-lm(grade~time)
summary(model)
plot(time,grade)
abline(model)

Then from that you can extract the linear regression equation, see if it look's correlated, and you can determine the predicted values from the linear regression equation

Answer 20

^That was great, I wish more helpers were like this guy, most just solve it for students and that is where the issues with this site occur.

Answer 21

I'm not too familiar with other software packages

Answer 22

We can also just plot it on some paper and scan it in to our teacher.
The predicted line of best fit is just going to be what line you think cuts through the data the best.
The line that you make for part B just comes from you taking 2 points, plugging into slope formula (to find the slope, obviously), and then plug that in to point-slope form.

Answer 23

Here's and unrelated example.
Find the line that passes through (2,5) and (4,11)
Slope = (y2-y1)/(x2-x1)
= (11 - 5)/(4 - 2)
= 6/2
= 3

Answer 24

Now plug into point slope form: y - y1 = m(x - x1)
....We just use the slope we found (3) for m, and plug in 2 and 5 for x1 and y1.
y - 5 = 3(x - 2)
Distribute into the ( )
y - 5 = 3x - 6
Now get y by itself by adding 5
y = 3x - 1
That is your line and works the exact same for lines of best fit.