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anyone wanna help me with this question about arithmetic sequences?
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Hey Ellie :) So to get from the 10th term to the 11th term we add some amount. \(\Large\rm 32+k\) to then get from the 11th term to the 12th term, we would add that same amount once again.\[\Large\rm (32+k)+k=106\] So to get from the 10th to the 12th, we added something twice.
If it's easier this way, maybe you can think of it like slope. Find the difference in the terms, and divide that by the difference in the term numbers.\[\Large\rm k=\frac{106-32}{12-10}\]
After you have your k value, You can setup the general form using the information we have:\[\Large\rm a_n=\color{orangered}{a_1}+(n-1)\color{royalblue}{k}\]
thank you!!!!
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