Question

A quadratic equation is shown below:

3x2 - 16x + 2 = 0

Part A: Describe the solution(s) to the equation by just determining the discriminant. Show your work. (3 points)

Part B: Solve 9x2 + 3x - 2 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points)

Part C: Solve 3x2 - 10x + 2 = 0 by using a method different from the one you used in Part B. Show the steps of your work. (3 points)

Answer 1

part A -> http://www.regentsprep.org/Regents/math/algtrig/ATE3/discriminant.htm

part B well, used the "appropriate method" then :)

Answer 2

BUT i dont know the appropriate method

Answer 3

well... have you covered quadratics yet?

Answer 4

these functions are just two quadratic ones....so....is assume you have covered the appropriate methods already

Answer 5

\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 6

a=3 b=-16 c=2

Answer 7

\[x=\frac{ 16\pm \sqrt{-16^{2}4(3)(2)} }{ 2(3) }\]

Answer 8

For part b, factorization will work.
9x^2 + 3x - 2 = 0
9x^2 + 6x - 3x - 2 = 0
3x(3x + 2) - 1(3x+2) = 0
(3x-1)(3x+2) = 0
x = 1/3, -2/3

For part c) use the above formula.
3x^2 - 10x + 2 = 0
a = 3, b = -10, c = 2

\(\Large x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a } = \frac{ 10\pm \sqrt{(-10)^{2}-4(3)(2)} }{ 2(3) } = ?\)

Answer 9

i dont know how to do that either

Answer 10

Solution via A - discrimintant of this quadratic equation, step by step:

http://www.hackmath.net/en/calculator/quadratic-equation?a=&b=&c=&eq2=3x2+-+16x+%2B+2+%3D+0