Medal and or a fan Part A: Divide (10x4y3 + 5x3y2 - 15x2y - 25x2y4) by -5x2y. Show your work, and justify each step. Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? Part C: What is the degree and classification of the polynomial you got in Part A?
@robtobey
@zepdrix
:o
what
\[\Large\rm \frac{10x^4y^3+5x^3y^2-15x^2y-25x^2y^4}{-5x^2y}\]So we need to do this division, yah?
yes sir
\[\Large\rm =\frac{10x^4y^3}{-5x^2y}+\frac{5x^3y^2}{-5x^2y}-\frac{15x^2y}{-5x^2y}-\frac{25x^2y^4}{-5x^2y}\]We can separate the terms like this. And do the division piece by piece. Should work out ok. :o
Or we can do factoring in the numerator if you're more comfortable with that.
Yah let's do that actually.. that makes more sense. Factoring.
Err no factoring would be simply doing the division anyway... blahhh how you wanna do this? :d
which is easiest
\[\Large\rm =\color{orangered}{\frac{10x^4y^3}{-5x^2y}}+\frac{5x^3y^2}{-5x^2y}-\frac{15x^2y}{-5x^2y}-\frac{25x^2y^4}{-5x^2y}\]What do you get for this first term? Divide the 10 and -5. Divide x^4 by x^2. (recall that when you divide terms with similar bases, you `subtract` the expoennts).
-2x^2y
10 divide -5 gives us -2. x^4 divide x^2 gives us x^(4-2) which is x^2. y^3 divide y gives us y^(3-1) which is y^2.\[\Large\rm \color{orangered}{-2x^2y^2}\]Mmmm ok very good! :) Do that same process with the other terms.
\[\Large\rm =\color{orangered}{-2x^2y^2}+\frac{5x^3y^2}{-5x^2y}-\frac{15x^2y}{-5x^2y}-\frac{25x^2y^4}{-5x^2y}\]
-1x^1y
-3xy -5xy^3
In the last two terms keep in mind that we're subtracting these negative values, so it will change them to positive, yes? \[\Large\rm =-2x^2y^2-xy-\frac{15x^2y}{-5x^2y}-\frac{25x^2y^4}{-5x^2y}\]
\[\Large\rm \frac{x^2}{x^2}\ne x\]
ok so -3 -5y^3
\[\Large\rm =-2x^2y^2-xy-(-3)-(-5y^3)\]Mmm ok good. Which simplifies a little bit.
By combining like terms?
No. No like-terms here. Just combine the negatives.
ok so its xy^4
I that correct @zepdrix
What..? I don't understand what you did...
I combined the negatives
There are no like-terms. You shouldn't be combining anything. Just simplify the negative signs. Example: \(\Large\rm -(-4)=+4\)
ok so -2x^2y^2 -xy + 3 + 5y^3
Yes.
o ok so is it the same thing with part B
For part B, If we had divided by x instead of x^2, we would be dividing by `one less power of x`. So each term would end up with `one more power of x`.
o ok I see thank you so much man
btw I hope you have a good Shabbat my Jewish brother
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