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OpenStudy (anonymous):
@zepdrix @SithsAndGiggles @nincompoop @ganeshie8
OpenStudy (anonymous):
What's the derivative of \(\dfrac{6}{x}\)?
OpenStudy (anonymous):
I don't know.....
OpenStudy (anonymous):
Well you have at least three ways to go about it. Power rule, quotient rule, or limit definition. Which of these are you familiar with the most?
OpenStudy (anonymous):
is it 3/2?
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OpenStudy (anonymous):
Close, but you're missing a negative sign.
Remember that \(\dfrac{1}{x}=x^{-1}\), so the power rule gives \(\dfrac{d}{dx}x^{-1}=(-1)x^{-1-1}=-x^{-2}=-\dfrac{1}{x^2}\).
OpenStudy (anonymous):
so -3/2?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
so this one would be 63, right? Find the derivative of f(x) = -2x2 + 11x at x = 9.
OpenStudy (anonymous):
@SithsAndGiggles
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OpenStudy (anonymous):
\(f(x)=-2x^2+11x\) ?
OpenStudy (anonymous):
If so, then I think you made a mistake in your derivative: \(f'(x)=-4x+11\).
Or you made a computational error: \(-4(9)+11=-36+11=-25\not=63\).