Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (dannyrod2000):

Rationalize

OpenStudy (dannyrod2000):

http://prntscr.com/4dadd0

OpenStudy (dannyrod2000):

hey @tejasvir

OpenStudy (anonymous):

hey danny

OpenStudy (dannyrod2000):

can you help me :)

OpenStudy (anonymous):

one sec. sorry my internet is really slow:P

OpenStudy (dannyrod2000):

k

OpenStudy (tylerd):

what could you multiply \[\sqrt{x+2}\] so that it is no longer a square root?

OpenStudy (tylerd):

\[\sqrt{3} \times \sqrt{3} = ?\]

OpenStudy (anonymous):

3

OpenStudy (dannyrod2000):

what he said :p

OpenStudy (anonymous):

you should multiply it with \[\sqrt{x+2}\]

OpenStudy (tylerd):

so \[\sqrt{x+2} \times \sqrt{x+2} = x+2\]

OpenStudy (anonymous):

ofcourse

OpenStudy (dannyrod2000):

oh ok

OpenStudy (tylerd):

but in this case its a denominator so

OpenStudy (tylerd):

and remember you have to multiply both the numerator and denominator by the same thing for it to come out as 1/1

OpenStudy (dannyrod2000):

yes i got that :)

OpenStudy (anonymous):

yes..u right the equation would be \[y=4\frac{ \sqrt{x=2} }{ x+2 }\]

OpenStudy (dannyrod2000):

\[so~4\sqrt{x+2}=?\]

OpenStudy (anonymous):

sorry sqrt (x+2) in numerator

OpenStudy (tylerd):

you cant simplify it further

OpenStudy (anonymous):

u can jst do one more step \[4\sqrt{x+2}=\sqrt{16x+32}\]

OpenStudy (dannyrod2000):

Thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!