Question

How do i rationalize a dewnominator

Answer 1

Multiply Both Top and Bottom by a Root. Sometimes you can just multiply both top and bottom by a root: ...

Multiply Both Top and Bottom by the Conjugate. There is another special way to move a square root from the bottom of a fraction to the top ... you multiply both top and bottom by the conjugate of the denominator.

Answer 2

first you spelled it wrong

Answer 3

nice dis is maths not english section

Answer 4

awesome u cant correct me ur grammr itself is worng

Answer 5

well...
lets get back to topic.

Answer 6

okay

Answer 7

cmon answer

Answer 8

chucho answered for me...

and you

Answer 9

oooh okay so even u had this doubt

Answer 10

@ganeshie8 ur good at maths pls ellaborate

Answer 11

Maybe a kind of example will be a great help.

In rationalizing numbers, you must know first what a rational number is. A rational number by the way is a number that can be represented by equation p/q, where p and q are both integers.

Say we have 1/sqrt(2) and you are asked to rationalize the denominator.
The first thing that will come into your mind of course is to represent sqrt(2) (the denominator) in terms of p/q without changing the value of the given.

Answer 12

okay

Answer 13

We know that sqrt(2) times sqrt(2) = 2, right?
So a kind of multiplying the denominator by sqrt(2) may convert the denominator into its rational form.

But we also target to not to change the given, which is 1/sqrt(2), therefore, we also need to multiply the numerator by sqrt(2). Therefore, we are multiplying the given with sqrt(2)/sqrt(2) = 1 (therefore, we will not change the value of the given)

So upon applying \[\frac{ 1 }{ \sqrt2 } (\frac{ \sqrt2 }{ \sqrt2 }) = \frac{ \sqrt2 }{ 2 }\]
Hence, the denominator is already rationalized.

Answer 14

we already represent the new denominator, 2 by p/q which is 2/1

Answer 15

wait can u use a little more compliated example

Answer 16

rationalize the denominator
\[\frac{ 1 }{ \sqrt2 - 1 }\]

Answer 17

which one dere r no numbers

Answer 18

@Yttrium http://prntscr.com/4ddyrj

Answer 19

1/(sqrt2 - 1)

Answer 20

brb