A farmer along the boundary of a square field of side 10 min in 40 sec.What will be the magnitude of displacement of 2 min 20 sec ?

Question

A  farmer along the boundary of a square field of  side 10 min in 40 sec.What will be the magnitude of displacement of 2 min 20 sec ?

anonymous · Answer

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aaronq · Answer

I dont think you pasted the question correctly.

anonymous · Answer

yes i did

anonymous · Answer

@aryandecoolest  the question is here

anonymous · Answer

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$$AC = \sqrt{(AB ^2  + BC ^2 )}  = \sqrt{(100+100) }  = 10√2 m$$
REST OF ALL YOU KNOW :)

anonymous · Answer

He will complete 1 round in 40 s. so speed= 1m/sec
So, distance covered in 2 min 20 s or 140 s is = 140 × 1 = 140 m

Now, Number of rounds of the square completed in moving through 140 m is = 140/40 = 3.5 rounds
so, In 3 rounds the displacement is zero. In 0.5 round the farmer reaches the diagonally opposite end of the square from his starting point
Hope it's clear now :D @Greaty

anonymous · Answer

yes thank u @aryandecoolest  u always help me.. :D

anonymous · Answer

oh!! glad to know, i try my best :) anytime ) @Greaty

anonymous · Answer

:D