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Mathematics 9 Online
OpenStudy (anonymous):

Find all polar coordinates of point P = (6, 31°).

OpenStudy (tylerd):

\[(r,\theta)\]

OpenStudy (anonymous):

I got (6,(31pi/180)+2 n pi) (-6,(31pi/180)+2 n pi) am i correct?

OpenStudy (tylerd):

is n any integer?

OpenStudy (anonymous):

theta

OpenStudy (anonymous):

?

OpenStudy (tylerd):

the +2n pi

OpenStudy (tylerd):

is n any integer?

OpenStudy (anonymous):

no

OpenStudy (jdoe0001):

P = (6, 31°). <---- that looks like a polar coordinate already

OpenStudy (anonymous):

Yeah, they are already in polar coordinates.

OpenStudy (tylerd):

ya but it wants you to find all

OpenStudy (tylerd):

so im guessing that is just the reference angle

OpenStudy (anonymous):

yep ^

OpenStudy (jdoe0001):

then -> (6,(31pi/180)+2 n pi) (-6,(31pi/180)+2 n pi) \(\Large \checkmark\)

OpenStudy (anonymous):

Did I do right by doing (6,(31pi/180)+2 n pi) (-6,(31pi/180)+2 n pi) the polar coordinate theta i turned it into (31pi/180)

OpenStudy (anonymous):

the 2 n pi signfies it going around yea?

OpenStudy (tylerd):

its n times 360 degrees or 2 pi ya

OpenStudy (anonymous):

n = pi

OpenStudy (jdoe0001):

right... but I gather you may also want to clarify that say \(n \in \mathbb{Z}\)

OpenStudy (anonymous):

ohhh alright

OpenStudy (anonymous):

thank you guys ^^

OpenStudy (tylerd):

2pi^2?

OpenStudy (jdoe0001):

yw

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