Mathematics
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OpenStudy (anonymous):
Find all polar coordinates of point P = (6, 31°).
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OpenStudy (tylerd):
\[(r,\theta)\]
OpenStudy (anonymous):
I got
(6,(31pi/180)+2 n pi)
(-6,(31pi/180)+2 n pi)
am i correct?
OpenStudy (tylerd):
is n any integer?
OpenStudy (anonymous):
theta
OpenStudy (anonymous):
?
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OpenStudy (tylerd):
the +2n pi
OpenStudy (tylerd):
is n any integer?
OpenStudy (anonymous):
no
OpenStudy (jdoe0001):
P = (6, 31°). <---- that looks like a polar coordinate already
OpenStudy (anonymous):
Yeah, they are already in polar coordinates.
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OpenStudy (tylerd):
ya but it wants you to find all
OpenStudy (tylerd):
so im guessing that is just the reference angle
OpenStudy (anonymous):
yep ^
OpenStudy (jdoe0001):
then -> (6,(31pi/180)+2 n pi)
(-6,(31pi/180)+2 n pi) \(\Large \checkmark\)
OpenStudy (anonymous):
Did I do right by doing
(6,(31pi/180)+2 n pi)
(-6,(31pi/180)+2 n pi)
the polar coordinate theta i turned it into (31pi/180)
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OpenStudy (anonymous):
the 2 n pi signfies it going around yea?
OpenStudy (tylerd):
its n times 360 degrees or 2 pi ya
OpenStudy (anonymous):
n = pi
OpenStudy (jdoe0001):
right... but I gather you may also want to clarify that say \(n \in \mathbb{Z}\)
OpenStudy (anonymous):
ohhh alright
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OpenStudy (anonymous):
thank you guys ^^
OpenStudy (tylerd):
2pi^2?
OpenStudy (jdoe0001):
yw