Question

Pls help!! I need to get a 90 on my precal final to get an A, and this is pretty much the only problem i dont know how to do.

State whether the given measurements determine zero, one, or two triangles.

C = 37°, a = 16, c = 14

Answer 1

bump

Answer 2

bump? hhhee

Answer 3

so... haemm have you covered the law of sines yet?

Answer 4

yea

Answer 5

I'm thinking on finding the other angles... and see maybe the other side.. to see what they give

Answer 6

ok, gimme a minute to find that real quick

Answer 7

\(\bf \cfrac{sin(C)}{c}=\cfrac{sin(A)}{a}\implies \cfrac{sin(C)\cdot a}{c}=sin(A)\implies \cfrac{sin(37^o)\cdot 16}{14}=sin(A)
\\ \quad \\
sin^{-1}\left[\cfrac{sin(37^o)\cdot 16}{14}\right]=\measuredangle A\)

Answer 8

a bit truncated... so \(\bf \cfrac{sin(C)}{c}=\cfrac{sin(A)}{a}\implies \cfrac{sin(C)\cdot a}{c}=sin(A)\\ \quad \\ \cfrac{sin(37^o)\cdot 16}{14}=sin(A)\implies

sin^{-1}\left[\cfrac{sin(37^o)\cdot 16}{14}\right]=\measuredangle A\)

Answer 9

Yea, so A=~43.455 and B=99.5

Answer 10

so.... that should mean that at least one triangle can be made

Answer 11

yea for sure, but how do we find if a second one can be made?

Answer 12

hmmm

Answer 13

meaning that the likelyhood is that
when the side of the angle given in this case

is smaller than one of the two legs of the other side, you can use another angle 180-"c" to make a 2nd triangle