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Mathematics 12 Online
OpenStudy (xbeenchantedx):

Solve the equation. Check for extraneous solutions. 10/x+4=15/4x+4

OpenStudy (xbeenchantedx):

\[\frac{ 10 }{ x+4 }=\frac{ 15 }{ 4x+4 }\]

OpenStudy (anonymous):

\[\frac{10}{x+4}=\frac{15}{4x+4}\iff 10(4x+4)=15(x+4)\] is a start

OpenStudy (anonymous):

i would then divide both sides by \(5\) to get \[2(4x+4)=3(x-4)\] and then multiply out etc

OpenStudy (anonymous):

typo there, i meant \[2(4x+4)=3(x+4)\]

OpenStudy (anonymous):

you good from there?

OpenStudy (xbeenchantedx):

Is the answer an extraneous solution? When I tried plugging in the answer into the original problem, I got a different answers on both sides of the equation.

OpenStudy (anonymous):

what did you get for your answer? the one you tried?

OpenStudy (anonymous):

to answer your question, no, the solution is not "extraneous" it works

OpenStudy (xbeenchantedx):

I got x=4/5

OpenStudy (anonymous):

me too lets check it

OpenStudy (anonymous):

\[\frac{ 10 }{ x+4 }=\frac{ 15 }{ 4x+4 }\] \[\frac{ 10 }{ \frac{4}{5}+4 }=\frac{ 15 }{ 4\times \frac{4}{5}+4 }\]

OpenStudy (anonymous):

to find the left hand side, multiply top and bottom by \(5\) and get \[\frac{50}{4+20}=\frac{50}{24}=\frac{25}{12}\]

OpenStudy (anonymous):

to find the right hand side, do the same thing multiply top and bottom by 5 and get \[\frac{75}{16+20}=\frac{75}{36}=\frac{25}{12}\]

OpenStudy (xbeenchantedx):

Oh now I get it. I made weird calculations when trying to simplify it and that messed me up. Thank you!!!

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