Solve the equation. Check for extraneous solutions. 10/x+4=15/4x+4
\[\frac{ 10 }{ x+4 }=\frac{ 15 }{ 4x+4 }\]
\[\frac{10}{x+4}=\frac{15}{4x+4}\iff 10(4x+4)=15(x+4)\] is a start
i would then divide both sides by \(5\) to get \[2(4x+4)=3(x-4)\] and then multiply out etc
typo there, i meant \[2(4x+4)=3(x+4)\]
you good from there?
Is the answer an extraneous solution? When I tried plugging in the answer into the original problem, I got a different answers on both sides of the equation.
what did you get for your answer? the one you tried?
to answer your question, no, the solution is not "extraneous" it works
I got x=4/5
me too lets check it
\[\frac{ 10 }{ x+4 }=\frac{ 15 }{ 4x+4 }\] \[\frac{ 10 }{ \frac{4}{5}+4 }=\frac{ 15 }{ 4\times \frac{4}{5}+4 }\]
to find the left hand side, multiply top and bottom by \(5\) and get \[\frac{50}{4+20}=\frac{50}{24}=\frac{25}{12}\]
to find the right hand side, do the same thing multiply top and bottom by 5 and get \[\frac{75}{16+20}=\frac{75}{36}=\frac{25}{12}\]
Oh now I get it. I made weird calculations when trying to simplify it and that messed me up. Thank you!!!
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