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Physics 14 Online
OpenStudy (anonymous):

Which graph best illustrates the relationship between the frequency of an object’s rotation as a function of the orbital radius? Note, centripetal force and mass are constant.

OpenStudy (anonymous):

OpenStudy (anonymous):

f = 2 * pi * r / v So, 'f' increases linearly with 'r' Therefore, picture 3. The straight line which increases along both axes.

OpenStudy (sidsiddhartha):

@pompeii00 i think there's a little mistake in ur equation here actually,its \[T=\frac{ 2 \pi R }{ V } \\where \\T=time~period~of ~revolution \\V=velocity~of ~the ~object \\T=radius\] again we know that-- \[T=\frac{ 1 }{ frequency }=\frac{ 1 }{ F } \\ so \\F=\frac{ 1 }{ T }=\frac{ 1 }{ \frac{ 2 \pi R }{ V } }=\frac{ V }{ 2 \pi R }\] so whAT we can see here is that frequency is inversely proportional to the radius of the orbit \[F ~~~\alpha~~~\frac{ 1 }{ R }\] so the graph should be a rectangular hyperbola like in option (A)|dw:1408250158747:dw|

OpenStudy (sidsiddhartha):

got this? @lolo123...

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