Mathematics
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OpenStudy (anonymous):
Verify the identity cot(x-pi/2) = -tan x
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OpenStudy (anonymous):
please help
OpenStudy (shamim):
cot(-(π/2-x))
right?
OpenStudy (anonymous):
no cot(x-pi/2)=-tanx
OpenStudy (shamim):
i took left hand side
OpenStudy (anonymous):
explain please
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OpenStudy (anonymous):
how to get the answer..i don't understand this
OpenStudy (shamim):
cot(x-π/2)=cot(-(π/2-x)=-cot(π/2-x)
right?
OpenStudy (anonymous):
yeah what would be the answer
OpenStudy (shamim):
=-tanx=right hand side
OpenStudy (anonymous):
so it would be cot(-pi/2-x)
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OpenStudy (anonymous):
sorry im really bad at math
OpenStudy (anonymous):
someone please help
OpenStudy (anonymous):
anyone!!!!
OpenStudy (shamim):
x-π/2=-(π/2-x)
right?
OpenStudy (anonymous):
why does it equal it can you please explain
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OpenStudy (shamim):
a-b=-(b-a)
right?
OpenStudy (anonymous):
ok yes
OpenStudy (shamim):
did u really get it?
OpenStudy (anonymous):
yes because in each thing a will be pos and b neg right? so that's why they are equal
OpenStudy (anonymous):
plase help
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OpenStudy (anonymous):
please
OpenStudy (shamim):
so why not
x-π/2=-(π/2-x)
OpenStudy (anonymous):
awww I get that part
OpenStudy (shamim):
ok very good
OpenStudy (shamim):
do u know
sin(π/2-30)=cos30
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OpenStudy (anonymous):
yes
OpenStudy (shamim):
ok
OpenStudy (anonymous):
which identity would i use:)
OpenStudy (shamim):
cot(π/2-x)= tan x
right?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
that true that's an identity i didn't see that..but how would you add the neg
OpenStudy (shamim):
now
sin(-x)=-sin x
right?
OpenStudy (anonymous):
yes
OpenStudy (shamim):
tan(-x)=-tan x
right
OpenStudy (anonymous):
yes
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OpenStudy (shamim):
in similar way
cot(-x)=-cot x
right?
OpenStudy (anonymous):
yes
OpenStudy (shamim):
sowe can write
cot(-(π/2-x))=-cot(π/2-x)
right?
OpenStudy (anonymous):
yes you can. but since the problem is cot(x-pi/2)....how would I add the neg since I don't think it can be changed to -cot(-x+pi/2) right?
OpenStudy (shamim):
but we can write
cot(x-π/2)=cot(-(π/2-x))
because x-π/2=-(π/2-x)
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OpenStudy (shamim):
right?
OpenStudy (anonymous):
ohh okay I see.
OpenStudy (anonymous):
so would it mean cot(-(pi/2-X) = -cot(pi/2-x)..like you said before
OpenStudy (shamim):
ya u r correct
OpenStudy (anonymous):
so -cot(pi/2-x) = -tanx right?
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OpenStudy (shamim):
ya
OpenStudy (anonymous):
ohh okay, Thank you so much for your help!!
OpenStudy (shamim):
welcome
OpenStudy (shamim):
anyway which grade u r
OpenStudy (anonymous):
12 grade
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OpenStudy (anonymous):
thank you so much again you are truly a life saver
OpenStudy (shamim):
which country?
OpenStudy (shamim):
i wanna solve ur every math if i can collect ur math book