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Calculus1
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How to find X ?
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move x2 to other side and think.you can solve this problem.
This is like \[x^{\frac{ 2 }{ 3 }} - x^{\frac{ 6 }{ 3 }} = 0\]
Factoring out, x^(2/3) you'll get.. \[x^{\frac{ 2 }{ 3 }} (1 - x^{\frac{ 4 }{ 3 }})\]
sorry, that should be equated to zero.
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Hence, you'll get \[x^{\frac{ 2 }{ 3 }} = 0\] so x = 0 On the other hand, you'll also get \[1- x^{\frac{ 4 }{ 3 }} = 0\] Hence, you'll get x = 1 Therefore, the only possible integer value for x are only 0 and 1. QED
Unless you're willing to try for complex solutions lol
Thank youuuu <3 what about finding x in this way ? |dw:1408276282193:dw|
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