A biologist is comparing the growth of a population of flies per week. She has devised an equation to solve for which day (x) the bullfrg would be able to eat the entire population. The equation is 2^x=3x-1. However, she has observed that the bullfrog can not eat more than seven flies in one week. Explain to the biologist how she can solve this on a graph using a system of equations. Identify any possible constraints to the situation.
@SolomonZelman
she can eat no more than 7 flies per week, so \(\normalsize\color{blue}{ y≤7x\LARGE\color{white}{ \rm │ }}\), where is the number of weeks, and y is the number of flies. \(\normalsize\color{blue}{ \LARGE\color{white}{ \rm │ }}\) Are you sure that the equation is, \(\normalsize\color{blue}{ 2^x=3x-1\LARGE\color{white}{ \rm │ }}\) ?
Yes, I am
But the only possible solution to that (the \(\normalsize\color{blue}{ 2^x=3x-1\LARGE\color{white}{ \rm │ }}\)) equation is 1.
I am not sure how to go about \(\normalsize\color{black}{ 2^x=3x-1\LARGE\color{white}{ \rm │ }}\)
I'm positive that's it... are you using the other equation we came up with as a system?
So perhaps as phi said we just need it for one 1.
one week*
I am not sure about this, maybe @phi @IMStuck since they are already here.
If we solve the given equation, and you got 1, then perhaps we're supposed to substitute the 1 in for x in the equation we created, which would allow us to solve for y. Right?
This question has been asked before. I'll look for the post.
Ok
Thank you!
http://openstudy.com/study#/updates/5372fefbe4b0c1175e755dc4 ganesh posted a graph showing the two possible solutions.
The constraint bullfrog can not eat more than seven flies in one week. probably means the frog can eat 7 flies on the first day (and none after that for a week), or 1 per day, or any combination , as long as it's less than 7 for that week. the plot shows x in days. to show the constraint, plot the line y= 7. No solution (in the first week, i.e. x<8) is allowed to be above 7
I think I understand...based on the problem, I'm supposed to finding the values for x, correct?
we solve the problem by finding where the two curves intersect, and then check that these points meet the constraint. We find two possible solutions (3,8) eat 8 flies on the 3rd day or (1,2) eat 2 flies on the first day only the second meets the constraint of 7 or fewer flies can be eaten in the first week.
That makes so much more sense. Thank you for explaining it to me!
yes. She has devised an equation to solve for which day (x) so you find x. you also find the corresponding y (to make sure we meet the constraint i.e. y value is less than 7 )
Thank you so much for the help!!
yw
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