Expand (s+2v)^5.
Pascals triangle.
I have \[s^5+s^4v+s^3v^2+s^2v^3+sv^4+v^5\] but I don't understand how to use pascal's triangle to get the coeficients.
\(\large\color{red}{ \bf 1 }\) \(\large\color{red}{ \bf 1~~~~~~~~~~~~~~1 }\) \(\large\color{red}{ \bf 1~~~~~~~~~~~~~2~~~~~~~~~~~~~~1 }\) \(\large\color{red}{ \bf 1~~~~~~~~~~~3~~~~~~~~~~~~~~~3~~~~~~~~~~~~~~1 }\) \(\large\color{red}{ \bf 1~~~~~~~~~~~4~~~~~~~~~~~~~6~~~~~~~~~~~~~~~4~~~~~~~~~~~~~1 }\) \(\large\color{blue}{ \bf 1~~~~~~~~~~5~~~~~~~~~~~~10~~~~~~~~~~~~~10~~~~~~~~~~~~~5~~~~~~~~~~~~~1 }\) \(\large\color{red}{ \bf 1~~~~~~~~~~6~~~~~~~~~~15~~~~~~~~~~~20~~~~~~~~~~~~~15~~~~~~~~~~~~6~~~~~~~~~~~~1 }\)
Do I just use everything in the 5th row for s and v, but then multiply all the coeficients of v by 2?
or the 10th row?
I chose the correct row, but there are two 10s and I didn;t notice that.
\(\normalsize\color{red}{ (s+2v)^5=\color{blue}{(1)}s^5+\color{blue}{(5)}s^4(2v)^1+\color{blue}{(10)}s^3(2v)^2+\color{blue}{(10)}s^2(2v)^3+\color{blue}{(5)}s^1(2v)^4+\color{blue}{(1)}(2v)^5.\LARGE\color{white}{ \rm │ }}\) Sorry it is like this.
\[s^5+53^42v+10s^32v^2+10s^22v^3+5s2v^4+2v^5\]?
not 53 but 5s^4
No
\(\normalsize\color{red}{ (s+2v)^5=\color{blue}{(1)}s^5+\color{blue}{(5)}s^4(2v)^1+\color{blue}{(10)}s^3(2v)^2+\color{blue}{(10)}s^2(2v)^3+\color{blue}{(5)}s^1(2v)^4+\color{blue}{(1)}(2v)^5.\LARGE\color{white}{ \rm │ }}\) working the 1st 2 terms \(\normalsize\color{red}{ (s+2v)^5=s^5+10s^4v+\color{blue}{(10)}s^3(2v)^2+\color{blue}{(10)}s^2(2v)^3+\color{blue}{(5)}s^1(2v)^4+(2v)^5.\LARGE\color{white}{ \rm │ }}\)
Do you understand how I am getting the first 2 terms (so far) ?
taking the 2 from 2v in the second term and multiplying it with the 5s^4?
Yes, and I am getting 10v^4. Good.
OK, and the rest is the same?
Or multiply the 2 onto the s in all of the terms?
\(\normalsize\color{red}{ (s+2v)^5=s^5+10s^4v+\color{blue}{(10)}s^3(2v)^2+\color{blue}{(10)}s^2(2v)^3+\color{blue}{(5)}s^1(2v)^4+(2v)^5.\LARGE\color{white}{ \rm │ }}\) Continue to the 3rd term, I am raising (2v) to the second power. (2v)²=2² × v²=4v² \(\normalsize\color{red}{ (s+2v)^5=s^5+10s^4v+\color{blue}{(10)}s^3(4)v^2+\color{blue}{(10)}s^2(2v)^3+\color{blue}{(5)}s^1(2v)^4+(2v)^5.\LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{red}{ (s+2v)^5=s^5+10s^4v+40s^3v^2+\color{blue}{(10)}s^2(2v)^3+\color{blue}{(5)}s^1(2v)^4+(2v)^5.\LARGE\color{white}{ \rm │ }}\)
Good with the third term ? Can you do the last 3 terms ?
Show me term by term please.
s^5
10s^4v
yes, those are the first 2. And the third term is ?
40s^3v^2?
Yes
Can you do the 4th term ?
80s^2v^3
80sv^4
32v^5
CORRECT, 80s²v³ would be the 4th term
And the 5th term ?
32v^5
forgetting the s....
\[s^5+10s^4v+30s^3v^2+80s^2v^3+80sv^4+32v^5\]?
32s^0v^5 for the 5th term?
Yes !
you got it correctly.
which simplifies to 32v^5
Yes..... ! You can post latex on same line as the regular letters, try using `\(\normalsize\color{black}{ }\)`
Copy paste the box, and type your thing in it, you will notice that you cantype on the same line as the box.
\(\normalsize\color{black}{?}\)
Yes, but you can type on the same line right after that question mark (or whatever you put in it) UNLIKE the EQUATION EDITOR .
\(\normalsize\color{black}{ like }\) this
\(\normalsize\color{black}{x^2 }\) = \(\normalsize\color{black}{x(x) }\)
I can type egular letters after it, like \(\normalsize\color{black}{ No }\) I am not :)
\(\normalsize\color{black}{O }\)K
:)
Thanks \(\normalsize\color{black}{ :D }\)
you can change the cor and fonts as well.... yw !
\(\normalsize\color{red}{:) }\)
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