How do you increase the stretch factor in the graph of y=x^3

Question

anonymous · Answer

$$y=x^3$$

acxbox22 · Answer

in the second equation you posted?

anonymous · Answer

they're the same

solomonzelman · Answer

STRETCHES.

f(x)= ∛x     ⇒     f(x)= $\normalsize\color{blue}{  \rm{a}   }$∛x  ,   when      `│a│> 1`        stretches vertically.

f(x)= ∛x     ⇒     f(x)= $\normalsize\color{blue}{  \rm{a}   }$∛x  ,   when      `│a│< 1`        stretches horizontally.

anonymous · Answer

And I want to increase the stretch factor by 8

solomonzelman · Answer

Showing on an example.

solomonzelman · Answer

you want to stretch it vertically or horizontally ?

anonymous · Answer

vertically

anonymous · Answer

$$y=8x^3$$ ?

solomonzelman · Answer

YES then you would add a coefficient of 8 in front of x³

solomonzelman · Answer

Because whatever x³ will equal, the 8, will make the y 8 times greater than that.

anonymous · Answer

so

solomonzelman · Answer

so ?

anonymous · Answer

for stretch factor of 8 vertically, moving 2 to the right, and 7 down, it is $$y=(8x-2)^3-7$$

solomonzelman · Answer

yes, but the parenthesis start after 8, not before it.

solomonzelman · Answer

$\normalsize\color{blue}{ y=8(x-2)^3-7\LARGE\color{white}{ \rm    │  }}$  like this

anonymous · Answer

$$y=8(x-2)^3-7$$

solomonzelman · Answer

Yeaaaah

anonymous · Answer

OK, thanks $\huge\color{blue}{:D      }$

solomonzelman · Answer

You welcome !