Question

solve for y: ln(y-2)-lnx+x =ln6

Answer 1

add, base it off, and add again ....

Answer 2

\[\ln (y-2)-lnx+x=\ln6\]
\[\ln \frac{ (y-2) }{x }=\ln6-x\]
Taking the left and right hand side to the power of e, we get,

Answer 3

\[\frac{ (y-2) }{ x }=e ^{\ln6-x}\]
\[\frac{ y-2 }{ x }=\frac{ 6 }{ e ^{x} }\]
\[y=\frac{ 6 }{ e ^{x} }+2\]

Answer 4

let me know if i did something wrong