Given the arithmetic sequence an = 2 − 5(n + 1), what is the domain for n?
All real numbers All integers where n ≥ 1 All integers where n > 1 All integers where n ≥ 2
any ideas?
I think its A @amistre64
hmm, all real numbers is rather impractical to me. after all, when we are developing a sequence, a list of things, we simply want to be able to count them. its hard to find the \(\pi^{th}\) term in a list of things
You can have a \(\normalsize\color{blue}{1}\)st, \(\normalsize\color{blue}{2}\)nd, \(\normalsize\color{blue}{3}\)rd, \(\normalsize\color{blue}{4}\)th (an on) term. But not ZEROth or -1st ....
some texts allow for a 0 starting term
am I wrong though?
Well, you mean index of a sigma from zero, but not in this case.
its not A, which is what my explanation boils down to
Yes, it definitely not ALL real numbers.
no, i mean that some texts start a sequence at a0 instead of a1. its the authors discretion
I haven't seen that.
But, perhaps...
My second guess would've been D
starting a list at the 2nd term is not generally advisable either.
I would smile at you, \(\normalsize\color{black}{\rm :D}\)
you are GUESSING, don't ... !
narrowing them down is what i perfer to call it lol
Their thought out guesses though, I don't know how to do it. I'm making an educated guess... but yes still a guess
spose you have a task to do, how do you go about writing down the steps to take? step2 step5 step3 step1 step4 or do you put them in some sort of more rational order?
rational order
then lets start with step1 and move from there. n>= 1
alright whats step 2?
if I had a sequence (for example) \(\normalsize\color{blue}{ 1,~~~~~~~~~~4,~~~~~~~~~7,~~~~~~~~~10,~~~~~~~~13....\LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{blue}{ 1st~~~~~~~2nd,~~~~~~3rd~~~~~~~4th~~~~~~~~5th\LARGE\color{white}{ \rm │ }}\)
step2 is what comes after step1, we dont care about the steps, we just want to know which order to do them in
the nth step is whatever the nth step is. but we know that we have to start with n=1, step1 and the rest fall in line
the domain for n is therefore: n=1,2,3,4,...
so B?
B seems to fit the bill yes
thankyou so much! @amistre64
good luck
B is correct (:
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