Question

Prime factorization with exponents

Answer 1

105

Answer 2

\(\normalsize\color{blue}{ 105=3\times5\times7 \LARGE\color{white}{ \rm │ }}\)

Answer 3

Just a bit more, and you would get to
\[\Large \sum_{n=1}^{whatever}(2n+1)~~~~~~~:)\]

Answer 4

Dafuq is that?

Answer 5

I need the factorization of the 105 with exponents

Answer 6

@mathmale

Answer 7

I gave you the prime factorization, it does not involve any exponents though.

Answer 8

so that's it?

Answer 9

If I'm reading this question correctly, you want to write the factors of 105 in exponential notation. Just borrow Solomon's result and insert exponents.\[105=5*3*7\]

Answer 10

becomes\[105=3^1*5^1*7^1\]... again, this is if you and I are not overlooking anything.

Answer 11

@solomonzelman: Hello.\[\Large \sum_{n=1}^{whatever}(2n+1)\]

Answer 12

is a SUMMATION. Daniel's math problem does NOT involve a summation.

Answer 13

I was making a joke, .. do you seriously think I am THAT stupid? Perhaps I am stupid, but that stupid ?! :)

Answer 14

Jajaja

Answer 15

did you mean to type j, or it is just really close to letter h ?

Answer 16

Daniel: Unless you have further questions about this parituclar math problem, please move on to the next problem you need to address.

Solomon, Daniel had no way to know that you were joking. At best that was a needless distraction. Better to stick to serious stuff, at least until you and the other person know one another well enough so that each of you knows when the other is joking.

Answer 17

30

Answer 18

XD

Answer 19

I think it would be 3^3 +3

Answer 20

Mister moderator xD... sure. I'll warn about the joke next time (if I don;t forget).

Answer 21

Am I right with the thing?

Answer 22

Mr. SolomonZelman: Best to stay on topic. No jokes at all until after the person asking the question is satisfied that he / she understands the problem solution and can go through it himself / herself.

Daniel: all you had to do was to factor 105 and to write the factors with exponents; the only exponents that will work are the 1, the 1 and the 1 in 5^1, 3^1 and 7^1. Stop there; no further work is necessary.

Answer 23

Thanks

Answer 24

And with a 30? would it be 3^3+3?

Answer 25

@mathmale

Answer 26

If you are trying to factor 30, the most factors you could identify would be four: 1, 2, 3, 5. We do not include 10 or 15 on this list, because 2*5 = 10 and 3*5 = 15.

3^3+3 does equal 30, yes, but "factors" imply multiplication (NO addition).

Answer 27

So sorry, Daniel, but I need to get offline. I'll be available later today, probably. Suggest you move forward and write up some questions to ask me (or other OS helpers) later.

Answer 28

Thanks

Answer 29

So what would it be?

Answer 30

List the factors of 30, assuming that 1 is a trivial factor. Which other digits must you multiply together to get 30? Remember: NO addition here; ALL multiplication to get 30.