Question

ALG 2 HELP PLEASE

Answer 1

Given the function f(x) = log3(x + 4), find the value of f-1(3). (1 point)

f-1(3) = 7
f-1(3) = 12
f-1(3) = 23
f-1(3) = 31

Answer 2

1/ solve for x of \(log_3 (x+4) =3\)
2/ apply f(x)=3 --> \(f^{-1}(3) =x\)
show me what do you get from step1

Answer 3

@OOOPS i don't know how to turn the original equation into an inverse, that's my main problem.

Answer 4

could you just teach me how to do that? i can do the rest?

Answer 5

Study this step:
\[f(x) = log_3(x+4) =3 \rightarrow 3^3 = x+4 \rightarrow 27 =x+4 \rightarrow x =23\]
And \(f(\color{red}{x})=A, ~~then~~f^{-1}(A) = \color{red}{x}\)
Apply to your problem,
\(f(\color{red}{23})=3, ~~then~~f^{-1}(3) = \color{red}{23}\)

Answer 6

By using this way, you don't have to find out inverse of f