Let f(x) = -4x + 7 and g(x) = 10x - 6. Find f(g(x)). -40x + 24 -40x + 31 -40x + 64 -40x + 70
@nikato
Hey, so for these kinds of question you're basically substituting g(x) into f(x) where ever the x is. So, \[f(g(x)) \implies -4(10x-6)+7\] now evaluate
\(\normalsize\color{blue}{ f(x) = -4x + 7\LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{blue}{ g(x) = 10x - 6\LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{blue}{ f(g(x)) = -4(10x - 6) + 7\LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{blue}{ f(g(x)) = -40x +24 + 7\LARGE\color{white}{ \rm │ }}\) \(\normalsize\color{blue}{ f(g(x)) = -40x +31\LARGE\color{white}{ \rm │ }}\)
Thanks @SolomonZelman Can I have One more question
I have one more I mean
sure
shore
Let f(x) = 2x - 6. Solve f^-1(x) when x = 2. -5 4 -2 7
Let me let me!
go ahead
Ok when the notation f^-1(x) implies you're looking for the inverse, so first lets find the inverse... Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x) Once you have the inverse, sub 2 for x and evaluate :)!
I don't get it
\[f(x) = 2x-6\] we have to find the inverse, so following the steps I gave you, \[y=2x-6\] now switch the x's and y's around, \[x=2y-6\] now solve for y, \[y=\frac{ x+6 }{ 2 }\] \[\implies f ^{-1}(x) = \frac{ x+6 }{ 2 }\] now substitute 2 for x and solve.
Okay so 8/2 =4
So B
One more please
Yeah.
Let f(x) = 24/3x -2 Find f(-2). -6 -3 3 6
What do you think?
If f(x) implies 24/3x-2 f(-2) implies ...?
I believe it is 24/12
Is it \[f(x) = \frac{ 24 }{ 3x-2 }~~~or~~~f(x) = \frac{ 24 }{ 3x }-2\]
Either way just plug in -2 for wherever the x is.
I am sorry I meant the 1st
K well just plug in -2 for x
3 x -2 = -6 - 2 = 8
Ah so the answer is 3
-3
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