Ask your own question, for FREE!
Physics 14 Online
OpenStudy (anonymous):

a machine gun fires 25g bullets at the rate of of 600 bullets per minute with a speed of 200m/s calculate the force required to keep the gun in position. pls explain

OpenStudy (anonymous):

i know who can help you

OpenStudy (anonymous):

google

OpenStudy (abhisar):

\(\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE \color{yellow}{\bigstar}\huge \color{orange}{\bigstar}\LARGE \color{red}{\bigstar}\huge \color{blue}{\bigstar}\LARGE\color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\huge \color{red}{\bigstar}\LARGE\color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE\color{yellow}{\bigstar}\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\\\color{white}{.}\\\Huge \rlap{\color{blue}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}}{\;\color{aqua}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}}\\\color{white}{.}\\\\\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE \color{yellow}{\bigstar}\huge \color{orange}{\bigstar}\LARGE \color{red}{\bigstar}\huge \color{blue}{\bigstar}\LARGE\color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\huge \color{red}{\bigstar}\LARGE\color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE\color{yellow}{\bigstar}\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\)

OpenStudy (abhisar):

Force = Rate of change in momentum, Rate of change in momentum = dmv/dt gun fires 600 bullets per minute or 10 bulllets per second => Force = (0.025*200)*10= 50N

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!