Question

Can you please help me with this ...
Water is flowing out of a conical funnel through its apex at a rate of 12 cubic inches per minute. If the funnel is initially full, how long will it take for it to be one-third-full? What is the height of the water level? Assume the radius to be 6 inches and the altitude of the cone to be 15 inches.
Please anyone ;/ ..

Answer 1

\[v=\pi 6^2\frac{ 15 }{ 3 }=565.49\]

so if we start with a volume of 565.49
and every minute we subtract 12.

we can find out the volume of the cone when its 1/3 full by doing this
\[\frac{ 1 }{ 3 }569.49=189.83\]

569.49 - 189.83 = 379.66
so that describes how much water has left the cone to be equal to 379.66 cubic inches.

ill leave it there, maybe that will get you started.

Answer 2

Oww thank you very much great help :) .. Thanks again :)