Question

rewrite in vertex form:
y= -x^2+4x-8
PLs. help I just need the guide in getting the k and H plsss.. Thanks! :)

Answer 1

\(\normalsize\color{blue}{ y= -x^2+4x-8\LARGE\color{white}{ \rm │ }}\)
\(\normalsize\color{blue}{ y= -x^2+4x-4-4\LARGE\color{white}{ \rm │ }}\)
\(\normalsize\color{blue}{ y= -(x^2-4x+4)-4\LARGE\color{white}{ \rm │ }}\)
\(\normalsize\color{blue}{ y= -(x-2)^2-4\LARGE\color{white}{ \rm │ }}\)

Answer 2

Parabola.
Opens down.
Not stretched vertically or horizontally.
Maximum point at (2,-4)

Answer 3

thank you! but how about in fraction

Answer 4

fraction ?

Answer 5

I gave you the vertex form, didn't I?

Answer 6

y = ⅕(2x²-4x+7) at first I would factor out of 2.
y = ⅖(x²-2x+3½)
And now, you have inside the parenthesis `2½` more than what you want to make the parenthesis a perfect square
Follow this carefully.
y = ⅖(x²-2x+1+2½)
y = ⅖(x²-2x+1)+(2½×⅖)
y = ⅖(x²-2x+1)+({5/2}×{2/5})
y = ⅖(x²-2x+1)+(1)
y = ⅖(x²-2x+1)+1
y = ⅖(x-1)²+1

Answer 7

Thank You so much sir! it helps a lot! :))

Answer 8

Anytime:)