Help with matrix problem : find the determinant given that A isa 3x3 matrix for which det(A)=-3 (a) det(3A^T) (b) det(2A^-1)
Okay, det(A) = -3, what's det(A^T) ?
No, that's the problem. Those are the only given.
I'm confused on what's supposed to do. lol
Yes, but you should know these two properties by heart, ok? Read carefully... \[\large \det(A^T) = \det(A)\][Transposes have the same determinant] \[\large \det(A^{-1}) = \frac1{\det(A)}\]
So, does it mean that that the answer is just for (a) is 3(-3)?
Or am I getting it wrong?
No... it isn't that simple, I'm afraid... but it IS still rather simple... Here's another property: \[\Large \det(cA) = c^n\det(A)\] Where n is the dimension of the matrix A.
So how do I actually do it? Can you show me an example. Help me with (a).
Certainly :) \[\Large \det(3A^T) = 3^3 \det(A^T)\] right?
Wait, so the size of the matrix is 3x3, right? So how do I get 3 as the exponent?
BECAUSE it's a 3x3 matrix :) If it was 4x4, the exponent would be 4 :D
I mean, how to solve for it, like you get it. Haha
I have a question, what if it's a 2x3? Haha
You're being silly... non-square matrixes don't even have determinants :D
Oooh. I don't know that. Hahaha
Ok, back to the problem.
\[\Large \det(3A^T) = 3^3 \det(A^T)\] You can work from here, you know the determinant of A^T, and you know 3^3
Ok thanks! Sorry man for late replies, I'm running errands. thanks!
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