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Mathematics 7 Online
OpenStudy (anonymous):

an = 4(−5)n − 1 an = 4(one fifth)n − 1 an = 0.4(5)n − 1 an = one fifth(4)n − 1

OpenStudy (anonymous):

OpenStudy (kirbykirby):

What happens to the y value when going from 4 to 0.8 ? 0.8 to 0.16 ?

OpenStudy (anonymous):

multiplied by .2?

OpenStudy (solomonzelman):

yes, exactly !

OpenStudy (solomonzelman):

And 0.2 = 1/5 So, your common ratio is 1/5 And you know that the first term, a1, is 4.

OpenStudy (anonymous):

ooohhh wow i didnt even think of that lol

OpenStudy (anonymous):

ok so that eliminates A and C

OpenStudy (anonymous):

with that being said it should be D right?

OpenStudy (solomonzelman):

if you say D, then it would mean that the ratio is 4, and the first term is 1/5 BUT it is the other way around.

OpenStudy (anonymous):

oh so your first term is always in front of your ratio?

OpenStudy (solomonzelman):

yes, because the ratio goes to the power of `n-1` for any `n`th term, right ?

OpenStudy (solomonzelman):

\(\large\color{blue}{ a_n=a_1\times r^{n-1}\LARGE\color{white}{ \rm │ }}\)

OpenStudy (solomonzelman):

it is always like this:)

OpenStudy (anonymous):

ok great tank you!

OpenStudy (solomonzelman):

Which option do you pick? (Just to make sure)

OpenStudy (anonymous):

B

OpenStudy (solomonzelman):

Yeah...\(\large\color{blue}{ a_n=5\times(⅕)^{n-1}\LARGE\color{white}{ \rm │ }}\)

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