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Mathematics 14 Online
OpenStudy (anonymous):

I need help with an absolute value question!

OpenStudy (anonymous):

OpenStudy (anonymous):

@johnweldon1993 could you help me please!

OpenStudy (johnweldon1993):

Firstly, you want to isolate that absolute value So we need to add 8 to both sides of this equation

OpenStudy (johnweldon1993):

\[\large 2|3x - 5| - 8 = 8\] \[\large 2|3x - 5| = 16\] Then we need to completely isolate it by dividing this whole equation by 2 (it will cancel the 2 out in front of the absolute value bars) \[\large |3x - 5| = 8\] Now we just split this into 2 equations \(\large 3x - 5 = 8\) and \(\large 3x - 5 = -8\) solve for 'x' in each of those

OpenStudy (anonymous):

|dw:1408374705797:dw|

OpenStudy (johnweldon1993):

Perfect! Except for the first one, they didn't want it THAT way \[\large 3x = 13\] \[\large x = \frac{13}{3}\] \[\large x = 4\frac{1}{3}\]

OpenStudy (johnweldon1993):

So which graph do we have? ^_^

OpenStudy (anonymous):

D?

OpenStudy (anonymous):

well 4 1/3 isnt an option.. but the -1 is there

OpenStudy (johnweldon1993):

...look at em all again (especially graph B :P

OpenStudy (anonymous):

oh oops, i totally didnt see that.. thank you! do you think you could help me with one more? im just trying to figure out how to set it up

OpenStudy (johnweldon1993):

Lol knew you would get it :P and yeah of course :)

OpenStudy (anonymous):

\[T= \frac{ 3U }{ E } solve for U\]

OpenStudy (johnweldon1993):

Alright so \[\large T = \frac{3U}{E}\] We want to get U by itself...if we multiply both sides of this equation by E... \[\large T \times E = \frac{3U}{\cancel{E}} \times \cancel{E}\] we will have \[\large TE = 3U\] Can you solve it from there?

OpenStudy (anonymous):

\[\frac{ TE }{ 3 } = U\]

OpenStudy (johnweldon1993):

Perfect! :)

OpenStudy (anonymous):

yay thank you so much! :)

OpenStudy (johnweldon1993):

No problem hun :)

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