I need help with an absolute value question!
@johnweldon1993 could you help me please!
Firstly, you want to isolate that absolute value So we need to add 8 to both sides of this equation
\[\large 2|3x - 5| - 8 = 8\] \[\large 2|3x - 5| = 16\] Then we need to completely isolate it by dividing this whole equation by 2 (it will cancel the 2 out in front of the absolute value bars) \[\large |3x - 5| = 8\] Now we just split this into 2 equations \(\large 3x - 5 = 8\) and \(\large 3x - 5 = -8\) solve for 'x' in each of those
|dw:1408374705797:dw|
Perfect! Except for the first one, they didn't want it THAT way \[\large 3x = 13\] \[\large x = \frac{13}{3}\] \[\large x = 4\frac{1}{3}\]
So which graph do we have? ^_^
D?
well 4 1/3 isnt an option.. but the -1 is there
...look at em all again (especially graph B :P
oh oops, i totally didnt see that.. thank you! do you think you could help me with one more? im just trying to figure out how to set it up
Lol knew you would get it :P and yeah of course :)
\[T= \frac{ 3U }{ E } solve for U\]
Alright so \[\large T = \frac{3U}{E}\] We want to get U by itself...if we multiply both sides of this equation by E... \[\large T \times E = \frac{3U}{\cancel{E}} \times \cancel{E}\] we will have \[\large TE = 3U\] Can you solve it from there?
\[\frac{ TE }{ 3 } = U\]
Perfect! :)
yay thank you so much! :)
No problem hun :)
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