Question

2x^(2/5)-x^(1/5)-1=0 Solve for x

Answer 1

this is *almost* the same problem

let y= x^(1/5)

Answer 2

So far I did y=x^(1/5)
Which leaves me with 2y^2-y-1=0
and then (2y+1)(y-1)=0

Answer 3

yes, and you get the same values for y as before

Answer 4

would x=y^5 ?

Answer 5

yes, if you have
\[ y= x^{\frac{1}{5}} \]
raise both sides to the 5th power:
\[ y^5= \left(x^{\frac{1}{5}} \right)^5 \\y^5=x^{\frac{1}{5}\cdot 5} \\
y^5= x
\]

Answer 6

notice we used the "rule"
\[ \left( a^b\right)^c = a^{bc} \]

Answer 7

So x is equal to 1 and -0.3125

Answer 8

(-½)^5 is not -0.3125

Answer 9

Are you sure? My calculator disagrees. :p

Answer 10

It might be an error on my part but I'm pretty sure it 's right

Answer 11

try again.

Answer 12

-0.03125

Answer 13

My mistake

Answer 14

yes, -1/32

Answer 15

I have another problem that is different then the two we did so I'll make another post. Thanks for all of your help.