Help please? Which equation represents the line passing through the point (4, −16) and is perpendicular to the line y equals negative two thirds x plus 8?
where are you stuck at?
How do I draw a line when I only have one point? There's probably a way but I'm not sure how
you are given a point and a 'slope'. the slope is just hidden at the moment in the information
Well perpendicular means they cross at a right angle right?
perpendicular lines have the property that their slopes are negative reciprocals of one another: if slope1 = 4/5 then the perp slope is -5/4
yes, they cross at right angles
So I should graph the line they give me first I guess
you are given a line with a slope of -2/3 and want to apply the perp slope to your solution. what is the perp slope of -2/3?
3/2?
yes now, the line they ask for has a slope of: 3/2 and passes thru the point: (4,-16) we have all the information now to make the line equation.
y = 3/2x... how do I find out what comes after that
well, since we have a point and a slope; we could very well use what is called the point slope form of a line and then work it to whatever format they have as an option: given a point (a,b), and a slope, m ^^^^ ^^^^ point slope form is just: y-b = m(x-a) which we can rework as: y = mx - ma + b if need be to get it into slope intercept form
Well the answers are a. y = 2/3x - 22 b. y = -2/3x - 22 c. y = -3/2x - 22 d. y = 3/2x - 22
then it looks like d is our most reasonable choice.
I don't understand where they got the -22 from though
-3(4)/2 - 16 = 22
.. = -22
Ooh I understand thank you!!
\[y-(-16)=\frac 32(x-(4))\] \[y=\frac 32x-(4)\frac{3}{2}-16\] \[y=\frac 32x-6-16\] ...
but since all the options end in -22, that part doesnt really matter to us, the 3/2 slope is the key to simply picking out the right option without all the hulla-ballou
Yeah! thank you for your help
option C....
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