Question

What is 3 to the power of 2 over 3 equal to?

cube root of 9

square root of 9

cube root of 27

square root of 27

Answer 1

square root of 9

Answer 2

oh you ment square root of 9?

Answer 3

\(\Large \bf { \\ \quad \\
a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad

\sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}
\\ \quad \\ \quad \\
3^{\frac{{\color{blue}{ 2}}}{{\color{red}{ 3}}}}\implies ?
}\)

Answer 4

\[3^{2}\div3\]

Answer 5

that would be 9 /3 which is 2

Answer 6

its 3x3=9

Answer 7

3x3/3=3

Answer 8

yeah... it is not so exactly written. It can be as jdoe001 said 2\(\scriptsize\color{slate}{^{\LARGE ⅔} }\), or it can be 2²/3.

Answer 9

*cough* it helps to use parentheses to group the proper ones *cough*

Answer 10

yeah the options sound more like jdoe

Answer 11

yeah parenthesis, or a "\(\scriptsize\color{slate}{^{\LARGE ⅔} }\)" symbol

Answer 12

\(\Large \bf {
a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad

\sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}
\\ \quad \\ \quad \\
3^{\frac{{\color{blue}{ 2}}}{{\color{red}{ 3}}}}\implies \sqrt[\square ?]{\square ?}
}\)

Answer 13

@jdoe0001sooo is it \[\sqrt[3]{3^2}\]

Answer 14

@jdoe0001 or wait no it would be \[\sqrt[2]{3^3}\]

Answer 15

yeap

Answer 16

\(\large \sqrt[2]{3^3}\implies \sqrt{27}\)

Answer 17

so now i simplify and its the last one right

Answer 18

yeap

Answer 19

thanks a bunch ;)

Answer 20

No, this is not right. The original question is \(\normalsize\color{black}{ 3^{\bf\LARGE⅔}}\).

\(\normalsize\color{black}{ 3^{\bf\LARGE⅔}=\sqrt[3]{3^2}=\sqrt[3]{9}}\)

Answer 21

hmmm

Answer 22

ohhh ahemm yea.... right... hold the mayo and onions =)

Answer 23

the 1st one you had was correct, myu bad =) so

Answer 24

\(\Large \bf {
a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad

\sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}
\\ \quad \\ \quad \\
3^{\frac{{\color{blue}{ 2}}}{{\color{red}{ 3}}}}\implies \sqrt[{\color{red}{ 3}}]{3^{\color{blue}{ 2}}}\implies \sqrt[3]{9}
}\)

Answer 25

yeah... nothing wrong calculations wise, just confused what the problem was. That is not bad at all.

Answer 26

oh okayas right the first time with the first problem i did before i corrected it lol so the first one?