Question

Two sequences have the same common difference. How many terms could the sequences have in common?

Answer 1

let the two equation be P1 and P2 with last terms as 100 and 90 repectively.
Let the common difference be 5 P3.
the last term of P3 cannot be greater than 90
let the 1st common no. be 11
\[11+ (n-1)5 \le 90\]
\[(n-1)5\le90-11=81\]
\[(n-1)\le80/5=17\]
n=18

Answer 2

Where did the numbers come from?

Answer 3

it was just an example

Answer 4

as common diff is same so let us assume it is d
starting term for first seq x
starting term for second seq y
Now there can be three case
x>y y<x or x=y

Answer 5

I think you can answer now

Answer 6

Thank you c:

Answer 7

np!
what's answer did you get?

Answer 8

I'm supposing that the answer can be infinitive since the sequence is

Answer 9

@ankit042

Answer 10

the answer depends on the sequence

Answer 11

Yes I agree in case x=y we will have all terms same but for other cases no terms will be same!

Answer 12

So in another sequence will it not have similar terms?

Answer 13

a=1,3,5,7,8,10.......100 terms
b=7,9,12......90 terms
the number of common terms would change

Answer 14

@jherrera98 sorry my bad in other cases also you can have same terms sorry I got confused

Answer 15

Ohh ok c: thank you ! @cj49 @ankit042

Answer 16

np.