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Mathematics 20 Online
OpenStudy (anonymous):

A toy rocket was launched from the ground. The function f(x) = -16x2 + 160x shows the height of the rocket f(x), in feet, from the ground at time x seconds.

OpenStudy (anonymous):

x = 10; it takes 10 seconds to reach the maximum height and 10 seconds to fall back to the ground x = 10; it takes 10 seconds to reach the maximum height and 20 seconds to fall back to the ground x = 5; it takes 5 seconds to reach the maximum height and 10 seconds to fall back to the ground x = 5; it takes 5 seconds to reach the maximum height and 5 seconds to fall back to the ground

OpenStudy (tylerd):

alright so we can use the vertex formula to find its max height.

OpenStudy (anonymous):

\[x=-b/2a\]

OpenStudy (tylerd):

yes

OpenStudy (tylerd):

-160/-32

OpenStudy (tylerd):

x=5 then y=?

OpenStudy (anonymous):

Take the derivative and set it equal to zero and solve from the max f'x = -32x +160 =0 x = 5 Then to solve from the time for when the ball hits the ground just solve the equation at 0 x(-16x +160) = 0, 10

OpenStudy (anonymous):

is it C

OpenStudy (tylerd):

hmm

OpenStudy (tylerd):

x is our seconds

OpenStudy (tylerd):

at x=10 we are at a height of 0

OpenStudy (tylerd):

at x=5 we are at our max height

OpenStudy (tylerd):

so it looks to me that it takes 5 seconds for it to fall back down to zero

OpenStudy (tylerd):

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