Need help with a radical equation. Open question for equation. Will give medals.

Question

jacksonjrb · Answer

$$\sqrt{2x+9}-\sqrt{x+1}=\sqrt{x+4}$$

anonymous · Answer

square both sides
then you will have to isolate the radical and do it again 
it is a pain

jacksonjrb · Answer

whats would it look like after you squared it. thats all i need

anonymous · Answer

first off another easy inspection tells you the answer is zero
when you square you get 
$$2x+9-2\sqrt{2x+9}\sqrt{x+1}-(x+1)=x+4$$

anonymous · Answer

combine like terms
put everything without the radical on the other sides
then square again

jacksonjrb · Answer

ok thanks.

anonymous · Answer

yw
don't forget to square the $-2$

jacksonjrb · Answer

I'm sorry. @satellite73 Could you please do the second step? Then I think I'll be good.

anonymous · Answer

$$2x+9-2\sqrt{2x+9}\sqrt{x+1}-(x+1)=x+4$$ distribute the $-$sign 
$$2x+9-2\sqrt{2x+9}\sqrt{x+1}-x-1=x+4$$ combine like terms 
$$x+8-2\sqrt{2x+9}=x+4$$

anonymous · Answer

it is late and i messed up the last one 
$$x+8-2\sqrt{2x+9}\sqrt{x+1}=x+4$$

jacksonjrb · Answer

@satellite73 Sorry again. :P One more step then I'm almost certain I'll be good.