Solving a distance, rate, time problem using a system of linear equations
@TylerD
@ziqbal103 @aryandecoolest
so it travels at 25mph upstream and 37mph downstream
yes it does
i think you can just take an average of the 2 to find it in still water
im not sure how id do this with a system of linear equations though
but why do you do so? that is the part i dont understand
so i get 31 mph in still water with a water current at 6
@TylerD
It easy calculate speed upstream and downstream and then substitute in this: \[U=1/2(a+b)\] \[V=1/2(a-b)\] where a and b are speed downstream and upstream and U and V are speed of boat in still water and in stream respectively...
ok..i was confused somewhere but now i get it. Thank u guys!!!!
i just know from physics half of Velocity final + velocity initial = avg velocity
oooh...that could wok too!!! there seem to be so many ways to do this
Let the speed of the boat in still water be x and the speed of the current be y. While going upwards, speed of boat = x-y time = 4 hours distance = 100 miles speed = dist/time x-y = 100/4 = 25
continue... @Brainybeauty
Okay So while going downwards, speed of boat = x+y time = 4 hours distance = 148 miles speed = dist/time x+y = 148/4 = 37
so then i find the value of x and the value of y?
So you can find x and y now?
yes
You basically have to make two equations from the given information and then solve them to get the answer. It is as simple as that.
amazing! thank you soooo much
U R welcome! :)
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