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Mathematics 7 Online
OpenStudy (anonymous):

Complex number questionsss :(

OpenStudy (anonymous):

OpenStudy (anonymous):

i dont even know how to start on (i). theres no W but the question ask to find W. or should it suppose to be W = -2iz ?

OpenStudy (phi):

do they mention a W earlier in the text?

OpenStudy (anonymous):

no they didnt..

OpenStudy (phi):

post their solution. maybe we can "reverse engineer" what they mean

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

heres the solution.. but after reading it i still dun understand =.=

OpenStudy (anonymous):

and im a independent student.. so i have no teacher.. my only teacher is openstudy xD

OpenStudy (phi):

It looks like a typo, and they meant w= -2iz

ganeshie8 (ganeshie8):

Looks you have a First edition textbook with all printing mistakes >.<

OpenStudy (anonymous):

yea i thought so too ><..

OpenStudy (anonymous):

can i know how does |-2i| = 2?

ganeshie8 (ganeshie8):

basically the question is about figuring out how the angle changes when you multiply a complex number by a pure imaginary number

OpenStudy (phi):

also, they are pretty sloppy about w vs \(w_1\) \[ i= \cos(\pi/2) + i \sin(\pi/2) = e^{i \frac{\pi}{2}} \]

ganeshie8 (ganeshie8):

think of |-2i| as |0-2i|

ganeshie8 (ganeshie8):

heard of "iteration in complex plane" before @HatcrewS

OpenStudy (anonymous):

erm.. nope.. only know the vectors.. :S

OpenStudy (phi):

and -2i is \[ -2 e^{i \frac{\pi}{2}} \] we should notice that -2 = \( 2 e^{i \pi} \) so that we have \[ 2 e^{i \frac{3\pi}{2}} \] match that with \[ M e^{i \theta} \] M is 2

OpenStudy (phi):

or as ganeshie points out, in rectangular form a+bi, M= sqr(a^2 + b^2) here -2i is 0 - 2 i and we get sqr(0+4)= 2

OpenStudy (anonymous):

ooh.. |z| = r = sqr(x^2 + y^2)

OpenStudy (phi):

yes

ganeshie8 (ganeshie8):

just to add to that, notice below when u multiply something by \(z\) : 1) multiiplying a "real number" by \(z\) changes the magnitude but never the angle 2) multiplying a "imaginary number" by \(z\) changes the angle overall : you need some imaginary part to rotate in complex plane : \(zi\) changes the angle of \(z\) by 90 degrees ccw \(-zi\) changes the angle of \(z\) by -90 degrees ccw

ganeshie8 (ganeshie8):

everytime you multiply \(i\), the vector gets rotated by 90 degrees ccw

OpenStudy (anonymous):

multiplying a "imaginary number" by z changes the angle . does it change the magnitude too ?

OpenStudy (anonymous):

ccw means what clockwise ? anti clockwise ?

ganeshie8 (ganeshie8):

ccw = counter clock wise opposite of your regular clock

OpenStudy (phi):

if the number has mag≠ 1 , multiplying will change the product's length.

OpenStudy (anonymous):

ohh.. i know it as anti clockwise xD

ganeshie8 (ganeshie8):

lets take a complex number, multiply \(i\) and see what exactly happens :)

ganeshie8 (ganeshie8):

|dw:1408460209278:dw|

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