Can I have help with this problem?

Question

anonymous · Answer

$$\frac{ 12x ^{6}y ^{2}+8x ^{4}y ^{3}+4x ^{2}y ^{4} }{ 4x ^{2}y }$$

anonymous · Answer

Assuming x ≠ 0 and y ≠ 0, what is the quotient of ^

mrnood · Answer

can you for instance work out:

$$\frac{ 4x ^{2}y ^{4} }{4x ^{2}y }$$

anonymous · Answer

I think I figured it out....

mrnood · Answer

good - well done.

anonymous · Answer

Sorry

dangerousjesse · Answer

Just multiply like exponents by each other and lessen it to $y^{24}$ and $x^{48}$.

anonymous · Answer

Well
$$12x ^{6}y ^{2}+8x ^{4}y ^{3}+4x ^{2}y ^{4}$$
all the terms have a 4 in common

mrnood · Answer

that is not correct @DangerousJesse 

you can break it up into 3 separate fractions (all with the denominator the same as above)

You will see that the demnomitaor 'cancels' with items in all the terms

mrnood · Answer

$$\frac{ a+b+c }{ d } = \frac{ a }{ d }+\frac{ b }{ d }+\frac{ c }{ d }$$

mrnood · Answer

go back to my FIRST reply - see if you can do the 'cancellation' (or division)

anonymous · Answer

I'm sorry @MrNood

anonymous · Answer

I asked this question without realizing I already knew how to do it? But I found the right answer

mrnood · Answer

OK - np

anonymous · Answer

Thank you for your help tho