Question

someone please help me with this D:

Answer 1

hold on give me a minute to evaluate this hun

Answer 2

it i same as
\[(27x^3y^6)^\frac{ 1 }{ 6 }\]
multiply exponents
\[27^\frac{ 1 }{ 6 } x ^\frac{ 1 }{2 }y\]

Answer 3

@Mokeira thats what i got but it said it was incorrect..

Answer 4

dang i got the same thing .... :/

Answer 5

i know.. i dont know how its wrong...

Answer 6

is there a way to simplify it more ?

Answer 7

tbh hun i dont know im trying my best to evaluate it but ill let you know if i get anything different

Answer 8

alright thanks <3

Answer 9

no problem hun

Answer 10

i guess you can do this
\[(3^3x^3y^6)^\frac{ 1 }{6 }=3^\frac{ 1 }{2 }x^\frac{ 1 }{ 2}y\]

Answer 11

hope you can read what i ave written lol

Answer 12

sadly it still came out incorrect..

Answer 13

yea i can read it i think he can also read it ....but i think that could be right doe .... its hard to tel cause this question is kind of challenging u feel me

Answer 14

@ganeshie8

Answer 15

since it's multiplied under the root you can solve them seperately

Answer 16

how ?

Answer 17

\[\Large \sqrt[6]{27x^3y^6}=\sqrt[6]{27}*\sqrt[6]{x^3}*\sqrt[6]{y^6}\]

Answer 18

note that you can only do this when the numbers/terms under the root are multiplied with each other, it will not work when they are added/subtracted

Answer 19

i hope you also know that \(\Large \sqrt[a]{x}=x^{\frac{ 1 }{ a }}\)

so \(\Large \sqrt[6]{y^6} = y^{ \frac{ 6 }{ 6 }}=y^1=y\)

Answer 20

i really have to go now though, so if you haven't solved it by the time i'm back or if noone else helps you solve the rest of it i'll continue helping you.

Answer 21

ive tried that step and still says its wrong.

Answer 22

simplify each of these factors seperately

Answer 23

have you tried writing it in exponential form ?

Answer 24

heres kind of an example..

Answer 25

tbh .... this question got me thinking ....it truly is challenging .. but ima ask for help to try to get you the right answer hun

Answer 26

thankkss

Answer 27

just give me some time ... is there a exact time that you need to turn this in love

Answer 28

i have to finish this lesson today.. its the last one.. but theres a few more questions like these..

Answer 29

ok well ima try my best to get this done ... ill keep u updated on wht i got love :)

Answer 30

thanks :) ill brb

Answer 31

k

Answer 32

im back

Answer 33

lol ok look love .....look at my page i posted yo question and people answered it so let me know if they did it correctly

Answer 34

yeah it was :) thankks! but i need help with a few more of those questions ..

Answer 35

lol good im glad i could help you in some way and send them to me so i cna post them ot maybe solve them myself :)

Answer 36

@joftheworld \[\Large \sqrt[6]{125x^3y^9z^6}=(125x^3y^9z^6)^{1/6}=125^{1/6}*x^{3/6}*y^{9/6}*z^{6/6}\]

Answer 37

\[\Large 125^{1/6}=\sqrt[6]{125}=\sqrt{125^{1/3}}=\sqrt{5}~(since~5*5*5=125)\]

Answer 38

\[\Large x^{3/6} = x^{1/2} = \sqrt{x}\]
\[\Large y^{9/6} = y^{3/2} = y\sqrt{y}\]
\[\Large z^{6/6} = z^{1} = z\]

\[\Large \sqrt[6]{125x^3y^9z^6}=\sqrt{5}\sqrt{x}y \sqrt{y}z=yz \sqrt{5xy}\]