Question

Write an equation for the conic section : Parabola with the vertex at (1,-2) and a focus at (1,1) ???

Answer 1

So it's going to roughly look like this

Answer 2

The equation you're going to use is
(y-h)^2=4p(x-k)

Answer 3

well thanks

Answer 4

I wasn't done...

Answer 5

ok

Answer 6

The vertex is (h, k). So what is the value for h and what is the value for k? Hint, they've already given it to you

Answer 7

1,-2

Answer 8

Right.

(y-h)^2=4p(x-k)
(h-1)^2=4p(x+2)

Now, p is the distance between the vertex and the focus. So go back to the graph and count the amount of units

Answer 9

ummm p=3 ??????

Answer 10

P is equal to 3, yes, so you multiply (4)(3)

Answer 11

12

Answer 12

So the final equation will be?

Answer 13

(y-1)^2=12(x+2) ?????

Answer 14

am i right ???

Answer 15

Yeah I'm double checking on a graphing calculator to make sure it's right

Answer 16

ok

Answer 17

Give me just a moment, please

Answer 18

Ah, I see. I was confused because graphed this equation is sideways. So, here's the actual equation,

(x-1)^2=12(y+2)

Just needed to switch the variables :)

Answer 19

okay well tht helps alot thks :) !

Answer 20

You're welcome :)