equation of a conic section : Ellipse - foci (2,-4) & (5,-4).. Verticies (-1,-4) & (8,-4) ???
I think this site has what we want. Try matching the information to the equation of ellipse: Ax2 + Cy2 + Dx + Ey + F = 0
okay thanks
First, we'll find the center using the midpoint formula. (-1,-4) & (8,-4) -> \[\large \frac{-1+8}{2},\frac{-4+-4}{2}=>(\frac{7}{2},-4)\]
ooooookkk then what
I'm just taking this step by step following this problem. I have no idea what I'm doing
weelll at least ur tyring thts more then anyone else is f'ing doing .... thnx
cuz i was dead serious when i said i was in a group home and i need to graduate before i can go home
My wife left me. We all have our problems. Sadly, unless you're paying our lives don't revolve around you. The best we can do is help at our leisure
tuf lyfe man i got u bruh aight les get it you need the general equation of an ellipse right?
thanks buddy figured that out but unless ur persistant enough nothings gonna get done for u or anyone else for that matter
yeah sham
first, we need to see if the ellipse is at the origin of a plane
so ill wolfram the coordinates sec.
its the equation for a conic section idk if thts the same thing
\[\large \frac{ x^2 }{ a^2 } + \frac{ y^2 }{ b^2 } = 1\] if its centered at the origin of a plane a is the radius along the x-axis b is the radius along the y-axis if its not then: \[\frac{ (x-h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\] a is the radius along the x-axis b is the radius along the y-axis h, k are the x,y coordinates of the ellipse's center try graphing the ellipse first with the foci/vertices
ok gimme a sec.
ok done .... now what
plug in the center I gave you into the second equation shamil gave you
in english ...... plz
plug in (7/2, -4) into the second equation i put up there ok? also use the image up there that bib put so u can find the values of a and b
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